Answer
$\displaystyle \left[\begin{array}{ll}
0 & -5\\
-25 & -20\\
-10 & 10
\end{array}\right]$
Work Step by Step
Given
$D=\displaystyle \left[\begin{array}{ll}
10 & 20\\
30 & 20\\
10 & 0
\end{array}\right]$
$C = \displaystyle \left[\begin{array}{ll}
2 & 3\\
1 & 0\\
0 & 2
\end{array}\right]$
Solve for X
$0.2(X + D) = C$
$X = 5C - D$
$ 5 \displaystyle \left[\begin{array}{ll}
2 & 3\\
1 & 0\\
0 & 2
\end{array}\right] - \displaystyle \left[\begin{array}{ll}
10 & 20\\
30 & 20\\
10 & 0
\end{array}\right]$
$ \displaystyle \left[\begin{array}{ll}
10 & 15\\
5& 0\\
0 & 10
\end{array}\right] - \displaystyle \left[\begin{array}{ll}
10 & 20\\
30 & 20\\
10 & 0
\end{array}\right]$
= $\displaystyle \left[\begin{array}{ll}
0 & -5\\
-25 & -20\\
-10 & 10
\end{array}\right]$
