Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.3 - Matrices and Systems of Linear Equations - 10.3 Exercises - Page 710: 28

Answer

$a. $ $\left\{\begin{array}{l} x-2z+2w=5\\ y+3z=-1\\ z-w=0\\ w=-1 \end{array}\right.$ $b.$ $(5,2,-1,-1)$

Work Step by Step

$a. $ $\left\{\begin{array}{l} x-2z+2w=5\\ y+3z=-1\\ z-w=0\\ w=-1 \end{array}\right.$ $b.$ Back substitute $w=-1 $ into $z-w=0$ $z-(-1)=0$ $z+1=0$ $z=-1$ Back substitute $z=-1 $ into $y+3z=-1$ $y+3(-1)=-1$ $y-3=-1$ $y=2$ Back substitute $, z=-1,w=-1 $ into $x-2(-1)+2(-1)=5$ $x+2-2=5$ $x=5$ Solution: $(5,2,-1,-1)$
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