Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.6 - Complex Numbers - 1.6 Exercises - Page 64: 80


$z=a+bi$ Therefore $z=\frac{}{.}(\frac{}{z})=a+bi$

Work Step by Step

$z=a+bi$ Find the conjugate of the complex number by changing the sign of their imaginary part: $\frac{}{z}=a-bi$ So $\frac{}{.}(\frac{}{z})=a+bi$ Therefore $z=\frac{}{.}(\frac{}{z})=a+bi$
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