Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.6 - Complex Numbers - 1.6 Exercises - Page 64: 48



Work Step by Step

$i^{10}=(i^{2})^{5}$ and $i^{2}=\sqrt -1\times\sqrt -1=-1$ hence $i^{10}=(-1)^{5}$. $(-1)^{5}=-1\times-1\times-1\times-1\times-1=-1$. Hence the asnwer written in the form $a+bi$ where $a$ represents the real part and $b$ represents the imaginary part is $-1$ because $a=-1$ and $b=0$ as there is no imaginary part.
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