Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.6 - Complex Numbers - 1.6 Exercises - Page 64: 31


$(6+5i)(2-3i)$ = $27-8i$

Work Step by Step

1. $(6+5i)(2-3i)$ 2. Multiply the two binomials together (use the FOIL method to distribute the First, Outer, Inner, and Last terms): $12-18i +10i-15i^{2}$ 3. Combine like terms: $12-8i-15i^{2}$ 4. Change $-15i^{2}$ to to 15, because $i^{2} = -1$ and $-15\times-1 = 15$: $12-8i+15$ 5. Combine like terms: $27-8i$
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