Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.6 - Complex Numbers - 1.6 Exercises - Page 64: 37



Work Step by Step

$\dfrac{1}{i}$ Multiply the fraction by $\dfrac{-i}{-i}$: $\Big(\dfrac{1}{i}\Big)\Big(\dfrac{-i}{-i}\Big)=\dfrac{-i}{-i^{2}}$ We know that $i^{2}=-1$, so we get: $\dfrac{-i}{-(-1)}=\dfrac{-i}{1}=-i$
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