Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.6 - Complex Numbers - 1.6 Exercises: 63

Answer

$x=\dfrac{1}{2}\pm\dfrac{\sqrt{7}}{2}i$

Work Step by Step

$x^{2}-x+2=0$ Use the quadratic formula to solve this equation. The formula is $x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. For this equation, $a=1$, $b=-1$ and $c=2$. Substitute the known values in the formula: $x=\dfrac{-(-1)\pm\sqrt{(-1)^{2}-4(1)(2)}}{2(1)}=\dfrac{1\pm\sqrt{1-8}}{2}=...$ $...=\dfrac{1\pm\sqrt{-7}}{2}=\dfrac{1}{2}\pm\dfrac{\sqrt{7}}{2}i$ The solution is $x=\dfrac{1}{2}\pm\dfrac{\sqrt{7}}{2}i$
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