Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises - Page 34: 97



Work Step by Step

$Factor$ $the$ $expression$ $completely:$ $12x^3 + 18x$ The common factor for both terms is 6x. $6x(2x^2+3)$ We can check the answer by distributing the 6x to both terms. $6x(2x^2+3) = (6x\times2x^2) + (6x\times 3)$ $= 12x^3 + 18x$
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