## Precalculus: Mathematics for Calculus, 7th Edition

$(2x-5)(4x^{2}+20x+25)$
Use the difference of squares to cubes to solve. (1) $8x^{3}-125$ (2) $(2)^{3}x^{3}-(5)^{3}$ (3) $(2x+5)(4x^{2}+2(2x)(5)+(5)^{2}$ (4) $(2x-5)(4x^{2}+20x+25)$