Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises: 120



Work Step by Step

Can begin by factoring out a factor of 2 hence $18y^{3}x^{2}-2xy^{4}=2(9y^{3}x^{2}-xy^{4})$. Can also factor out a factor of $y^3$ hence $2(9y^{3}x^{2}-xy^{4})=2y^{3}(9x^{2}-xy)$. Can then also factor out an $x$ hence $2y^{3}(9x^{2}-xy)=2yx^{3}(9x-y)$. The original expression is now fully factorized.
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