## Precalculus: Mathematics for Calculus, 7th Edition

$x^{5/2}-x^{1/2}=\sqrt{x}(x-1)(x+1)$
$x^{5/2}-x^{1/2}$ Take out common factor $x^{1/2}$: $x^{5/2}-x^{1/2}=x^{1/2}(x^{4/2}-1)=\sqrt{x}(x^{2}-1)=...$ To finish the factoring process, factor the difference of squares inside the parentheses: $...=\sqrt{x}(x-1)(x+1)$