Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises: 91



Work Step by Step

$x^{5/2}-x^{1/2}$ Take out common factor $x^{1/2}$: $x^{5/2}-x^{1/2}=x^{1/2}(x^{4/2}-1)=\sqrt{x}(x^{2}-1)=...$ To finish the factoring process, factor the difference of squares inside the parentheses: $...=\sqrt{x}(x-1)(x+1)$
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