Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 9 - Analytic Geometry - Section 9.7 Plane Curves and Parametric Equations - 9.7 Assess Your Understanding - Page 714: 8

Answer

See graph, $2x-y+10=0$

Work Step by Step

1. See graph for $(t-3,2t+4)$ over $0\le t\le 2$ 2. From $x=t-3$, we have $t=x+3$, thus $y=2(x+3)+4$ or $2x-y+10=0$
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