Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 9 - Analytic Geometry - Section 9.7 Plane Curves and Parametric Equations - 9.7 Assess Your Understanding - Page 714: 12

Answer

See graph, $y=x-8$

Work Step by Step

1. See graph for $(\sqrt t+4,\sqrt t-4)$ over $t\ge0$ 2. From $x=\sqrt t+4$, we have $\sqrt t=x-4$, thus $y=\sqrt t-4=x-8$
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