Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 9 - Analytic Geometry - Section 9.7 Plane Curves and Parametric Equations - 9.7 Assess Your Understanding - Page 714: 7

Answer

See graph, $x-3y+1=0$

Work Step by Step

1. See graph for $(3t+2,t+1)$ over $0\le t\le 4$ 2. From $y=t+1$, we have $t=y-1$, thus $x=3t+2=3(y-1)+2$ or $x-3y+1=0$
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