Answer
See graph, $y=2x^2, x\ge0$
Work Step by Step
1. See graph for $(\sqrt {2t},4t)$ over $t\ge 0$
2. From $y=4t$, we have $t=y/4$, thus $x=\sqrt {2t}=\sqrt {\frac{y}{2}}$ or $y=2x^2, x\ge0$
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