Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 9 - Analytic Geometry - Section 9.7 Plane Curves and Parametric Equations - 9.7 Assess Your Understanding - Page 714: 10

Answer

See graph, $y=2x^2, x\ge0$

Work Step by Step

1. See graph for $(\sqrt {2t},4t)$ over $t\ge 0$ 2. From $y=4t$, we have $t=y/4$, thus $x=\sqrt {2t}=\sqrt {\frac{y}{2}}$ or $y=2x^2, x\ge0$
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