Answer
See graph, $\frac{x^2}{4}+\frac{y^2}{9}=1$
Work Step by Step
1. See graph for $(2cos(t),3sin(t))$ over $0\le t\le \pi$
2. Use $cos^2(t)+sin^2(t)=1$, we have $\frac{x^2}{4}+\frac{y^2}{9}=1, y\ge0$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.7 Plane Curves and Parametric Equations - 9.7 Assess Your Understanding - Page 714: 20
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