Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.7 The Cross Product - 8.7 Assess Your Understanding - Page 652: 48

Answer

$\sqrt {217}$

Work Step by Step

1. Find the vectors $\vec {P_1P_2}=< 4, 1,-3>$ and $\vec {P_1P_3}=< 4, -1, 0>$ 2. Find the cross product $\vec {P_1P_2}\times\vec {P_1P_3} = <(1(0)-(-3)(-1)),(-3(4)-4(0)),(4(-1)-1(4))>=<-3,-12,-8>$ 3. We have the area $A=||\vec {P_1P_2}\times\vec {P_1P_3} || =\sqrt {3^2+12^2+8^2}=\sqrt {217}$
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