Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.7 The Cross Product - 8.7 Assess Your Understanding - Page 652: 22

Answer

a) $v \times w =6i+4j +6k$ b)$w \times v=-6i-4j-6k$ c) $ v \times v =0$ d) $ w \times w =0$

Work Step by Step

Let us consider two vectors $v=xi+yj+zk$ and $w=pi+qj+rk$, then cross product of two vectors $v$ and $w$ can be computed in the form of determinate as : $ v \times w=\begin{vmatrix} i & j & k \\ x & y & z \\ p & q & r \\ \end{vmatrix}$Supposes that the two vectors can be represented as: $v=xi+yj+zk$ and $w=pi+qj+rk$, then their cross product of such vectors can be obtained in the form of determinate as : $ v \times w=\begin{vmatrix} i & j & k \\ x & y & z \\ p & q & r \\ \end{vmatrix}$ a) $v \times w =[(-3)(-2)-(0)(3)] i -j [(2)(-2) - (0)(0)]+k [(2)(3) -(-3) (0)]=6i+4j +6k$ b) Since, a cross or vector product is not commutative. So we can write as: $v \times w= -w \times v$ So, $w \times v=-6i-4j-6k$ c) We know that for the two mutually perpendicular vectors, we have: $v \times v = 0$ d) We know that for the two mutually perpendicular vectors, we have: $w \times w =0$
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