## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$9i+7j+3k$
Let us consider two vectors $v=xi+yj+zk$ and $w=pi+qj+rk$. Then cross product of the two vectors $v$ and $w$ can be computed in the form of determinant as: $v \times w=\begin{vmatrix} i & j & k \\ x & y & z \\ p & q & r \\ \end{vmatrix}$ We have: $det =v \times u =[(3)(1)-(2)(-3)] i -j [(-3)(1) - (2)(2)]+k [(-3)(-3) -(3) (2)]=9i+7j+3k$