Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.7 The Cross Product - 8.7 Assess Your Understanding - Page 652: 25



Work Step by Step

Let us consider two vectors $v=xi+yj+zk$ and $w=pi+qj+rk$. Then cross product of the two vectors $v$ and $w$ can be computed in the form of determinant as: $ v \times w=\begin{vmatrix} i & j & k \\ x & y & z \\ p & q & r \\ \end{vmatrix}$ We have: $det =v \times u =[(3)(1)-(2)(-3)] i -j [(-3)(1) - (2)(2)]+k [(-3)(-3) -(3) (2)]=9i+7j+3k$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.