Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.7 The Cross Product - 8.7 Assess Your Understanding - Page 652: 15

Answer

$v \times w =5i +5j +5k$ $w \times v=-5i-5j-5k$ and $ v \times v = w \times w =0$

Work Step by Step

Let us consider two vectors $v=xi+yj+zk$ and $w=pi+qj+rk$. Then cross product of the two vectors $v$ and $w$ can be computed in the form of the determinant as: $ v \times w=\begin{vmatrix} i & j & k \\ x & y & z \\ p & q & r \\ \end{vmatrix}$ We have: $det =v \times w =[(-3)(-1)-(-2)(1)] i -j [(2)(-1) - (1)(3)]+k [(2)(-2) -(-3) (3)]=5i +5j +5k$ Recall that $v \times w= -w \times v=-5i-5j-5k$ and $ v \times v = w \times w =0$
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