Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.7 The Cross Product - 8.7 Assess Your Understanding - Page 652: 47

Answer

$\sqrt {555}$

Work Step by Step

1. Find the vectors $\vec {P_1P_2}=<-3,1,4>$ and $\vec {P_1P_3}=$<-1,-4,3> 2. Find the cross product $\vec {P_1P_2}\times\vec {P_1P_3} = <(1(3)-4(-4)),(4(-1)-(-3)(3)),(-3(-4)-1(-1))>=<19,5,13>$ 3. We have the area $A=||\vec {P_1P_2}\times\vec {P_1P_3} || =\sqrt {19^2+5^2+13^2}=\sqrt {555}$
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