Answer
$A \approx52.4^\circ$
$B \approx29.7^\circ$
$C\approx 97.9^\circ$
Work Step by Step
1. Use the Law of Cosines, $A=cos^{-1}(\frac{(5)^2+(10)^2-(8)^2}{2(5)(10)})\approx52.4^\circ$
2. Use the Law of Cosines, $B=cos^{-1}(\frac{(8)^2+(10)^2-(5)^2}{2(8)(10)})\approx29.7^\circ$
3. Find the third angle $C\approx180-52.4-29.7=97.9^\circ$