Answer
$19.81\ unit^2$
Work Step by Step
1. Use the Law of Cosines, $A=cos^{-1}(\frac{(10)^2+(5)^2-(8)^2}{2(10)(5)})\approx52.4^\circ$
2. Use $c=10$ as the base, we have the area $K=\frac{1}{2}(10)(5sin52.4^\circ)\approx19.81\ unit^2$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 7 - Applications of Trigonometric Functions - Chapter Test - Page 580: 10
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