Answer
$ 0$
Work Step by Step
$sin40^\circ-cos50^\circ=sin40^\circ-sin(90^\circ-50^\circ)=sin40^\circ-sin40^\circ=0$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 7 - Applications of Trigonometric Functions - Chapter Test - Page 580: 2
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