Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Chapter Test - Page 580: 4

Answer

$C =117^\circ$ $b \approx6.85$, $c \approx16.30$

Work Step by Step

1. Find the third angle $C=180-41-22=117^\circ$ 2. Use the Law of Sines $\frac{12}{sin41^\circ}=\frac{b}{sin22^\circ}=\frac{c}{sin117^\circ}$ 3. $b=\frac{12sin22^\circ}{sin41^\circ}\approx6.85$, $c=\frac{12sin117^\circ}{sin41^\circ}\approx16.30$
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