Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Chapter Test - Page 580: 1

Answer

$sin\theta =\frac{\sqrt 5}{5}$, $cos\theta =\frac{2\sqrt 5}{5}$, $tan\theta =\frac{1}{2}$, $cot\theta =2$, $sec\theta =\frac{\sqrt 5}{2}$, $csc\theta = \sqrt 5 $.

Work Step by Step

Let $x=6,y=3$, we have $r=\sqrt {6^2+3^2}=3\sqrt 5$, thus $sin\theta=\frac{y}{r}=\frac{\sqrt 5}{5}$, $cos\theta=\frac{x}{r}=\frac{2\sqrt 5}{5}$, $tan\theta=\frac{y}{x}=\frac{1}{2}$, $cot\theta=\frac{x}{y}=2$, $sec\theta=\frac{r}{x}=\frac{\sqrt 5}{2}$, $csc\theta=\frac{r}{y}= \sqrt 5 $.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.