Answer
$(f\circ g)(x)=-2cos(x)$ and $(g\circ f)(x)=cos(-2x)$.
See graph.
Work Step by Step
1. Given $f(x)=-2x$ and $g(x)=cos(x)$, we have $(f\circ g)(x)=-2cos(x)$ and $(g\circ f)(x)=cos(-2x)$.
2. See graph.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.4 Graphs of the Sine and Cosine Functions* - 5.4 Assess Your Understanding - Page 433: 83
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