Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.4 Graphs of the Sine and Cosine Functions* - 5.4 Assess Your Understanding - Page 433: 71

Answer

$y=1-cos(\frac{4\pi}{3} x)$

Work Step by Step

1. Based on the given graph, we can initially identify that it resembles a graph of negative cosine shifted 1 unit up. 2. We can determine the amplitude $|A|=1$, period $p=\frac{3}{2}$, passing $(0,0)$. 3. Write a model as $y=1-cos(\omega x)$ 4. We have $\frac{2\pi}{\omega}=\frac{3}{2}$, thus $\omega=\frac{4\pi}{3}$ 5. The equation is $y=1-cos(\frac{4\pi}{3} x)$
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