Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.4 Graphs of the Sine and Cosine Functions* - 5.4 Assess Your Understanding - Page 433: 75

Answer

$y=-4cos(3x)$

Work Step by Step

1. Based on the given graph, we can initially identify that it resembles a graph of negative cosine. 2. We can determine the amplitude $|A|=4$, period $p=\frac{2\pi}{3}$, passing $(0,-4)$. 3. Write a model as $y=-4cos(\omega x)$ 4. We have $\frac{2\pi}{\omega}=\frac{2\pi}{3}$, thus $\omega=3$ 5. The equation is $y=-4cos(3x)$
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