Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.4 Graphs of the Sine and Cosine Functions* - 5.4 Assess Your Understanding - Page 433: 79

Answer

$\frac{\sqrt 2}{\pi}$.

Work Step by Step

1. Given $f(x)=sin(\frac{x}{2})$, we have $f(0)=sin(\frac{0}{2})=0$ and $f(\frac{\pi}{2})=sin(\frac{\pi}{4})=\frac{\sqrt 2}{2}$. 2. We have the average rate of change as $R=\frac{f(\frac{\pi}{2})-f(0)}{\frac{\pi}{2}-1}=\frac{\frac{\sqrt 2}{2}}{\frac{\pi}{2}}=\frac{\sqrt 2}{\pi}$.
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