## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson

# Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 403: 96

#### Answer

$\dfrac{1}{2}$

#### Work Step by Step

Let us consider: $g(\theta)=\cos \theta$ We are given that $\theta=60^{\circ}$ We know form the unit circle that $\cos (60^{\circ})=\cos (\dfrac{\pi}{3})=\dfrac{1}{2}$ Thus, we have: $g(\theta)=cos(60^{\circ}) \\=cos\dfrac{\pi}{3} \\ =\dfrac{1}{2}$

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