Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 403: 93



Work Step by Step

We need to compute $\csc (\theta)$. We are given that $\sin \theta=\dfrac{1}{5}$ Since, $\csc (\theta) =\dfrac{1}{\sin (\theta)}$ Thus, we have: $\csc (\theta) =\dfrac{1}{\sin (\theta)} \\=\dfrac{1}{\frac{1}{5}} \\=5$
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