## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$5$
We need to compute $\csc (\theta)$. We are given that $\sin \theta=\dfrac{1}{5}$ Since, $\csc (\theta) =\dfrac{1}{\sin (\theta)}$ Thus, we have: $\csc (\theta) =\dfrac{1}{\sin (\theta)} \\=\dfrac{1}{\frac{1}{5}} \\=5$