Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 403: 56

Answer

1. $sin390^\circ= \frac{1}{2}$. 2. $cos390^\circ= \frac{\sqrt 3}{2}$. 3. $tan390^\circ= \frac{\sqrt 3}{3}$. 4. $cot390^\circ= \sqrt 3$. 5. $sec390^\circ= \frac{2\sqrt 3}{3}$. 6. $csc390^\circ= 2$.

Work Step by Step

1. $sin390^\circ=sin(360+30)^\circ=sin30^\circ=\frac{1}{2}$. 2. $cos390^\circ=cos(360+30)^\circ=cos30^\circ=\frac{\sqrt 3}{2}$. 3. $tan390^\circ=tan(360+30)^\circ=tan30^\circ=\frac{\sqrt 3}{3}$. 4. $cot390^\circ=\frac{1}{tan390^\circ}=\sqrt 3$. 5. $sec390^\circ=\frac{1}{cos390^\circ}=\frac{2\sqrt 3}{3}$. 6. $csc390^\circ=\frac{1}{sin390^\circ}=2$.
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