Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 403: 60

Answer

1. $sin(-240^\circ)= \frac{\sqrt 3}{2}$. 2. $cos(-240^\circ)= -\frac{1}{2}$. 3. $tan(-240^\circ)= -\sqrt 3$. 4. $cot(-240^\circ)= -\frac{\sqrt 3}{3}$. 5. $sec(-240^\circ)= -2$. 6. $csc(-240^\circ)= \frac{2\sqrt 3}{3}$.

Work Step by Step

1. $sin(-240^\circ)=-sin(240^\circ)=-sin(180+60)^\circ=sin(60)^\circ=\frac{\sqrt 3}{2}$. 2. $cos(-240^\circ)=cos(240^\circ)=cos(180+60)^\circ=-cos(60)^\circ=-\frac{1}{2}$. 3. $tan(-240^\circ)=-tan(240^\circ)=-tan(180+60)^\circ=-tan(60)^\circ=-\sqrt 3$. 4. $cot(-240^\circ)=\frac{1}{tan(-240^\circ)}=-\frac{\sqrt 3}{3}$. 5. $sec(-240^\circ)=\frac{1}{cos(-240^\circ)}=-2$. 6. $csc(-240^\circ)=\frac{1}{sin(-240^\circ)}=\frac{2\sqrt 3}{3}$.
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