Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 403: 55

Answer

1. $sin405^\circ= \frac{\sqrt 2}{2}$. 2. $cos405^\circ= \frac{\sqrt 2}{2}$. 3. $tan405^\circ=1$. 4. $cot405^\circ= 1$. 5. $sec405^\circ= \sqrt 2$. 6. $csc405^\circ= \sqrt 2$.

Work Step by Step

1. $sin405^\circ=sin(360+45)^\circ=sin45^\circ=\frac{\sqrt 2}{2}$. 2. $cos405^\circ=cos(360+45)^\circ=cos45^\circ=\frac{\sqrt 2}{2}$. 3. $tan405^\circ=tan(360+45)^\circ=tan45^\circ=1$. 4. $cot405^\circ=\frac{1}{tan405^\circ}=1$. 5. $sec405^\circ=\frac{1}{cos405^\circ}=\sqrt 2$. 6. $csc405^\circ=\frac{1}{sin405^\circ}=\sqrt 2$.
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