Answer
$\{x|x\ne-2 \}$.
H.A. $y=1$, V.A. $x=-2$, O.A. $none$.
Work Step by Step
Step 1. Given $R(x)=\frac{x^2+3x+2}{(x+2)^2}=\frac{(x+1)(x+2)}{(x+2)^2}=\frac{x+1}{x+2}$, we can find the domain $x\ne-2$ or $\{x|x\ne-2 \}$.
Step 2. We can find horizontal asymptote(s) H.A. $y=1$, vertical asymptote(s) V.A. $x=-2$, oblique asymptote(s) O.A. $none$.
