Answer
$-3,2$.
Work Step by Step
Step 1. For $f(x)=2x^4+2x^3-11x^2+x-6$, list possible rational zeros $\frac{p}{q}:\pm1,\pm2,\pm3,\pm6,\pm\frac{1}{2},\pm\frac{3}{2}$.
Step 2. Use synthetic division as shown to find zero(s) $x=-3,2$.
Step 3. Use the quotient to find other zero(s) $2x^2+1=0$, no real solutions.
