Answer
$\{x|x\ne\pm3 \}$
H.A. $y=0$, V.A. $x=\pm3$, O.A. $none$.
Work Step by Step
Step 1. Given $R(x)=\frac{x+2}{x^2-9}=\frac{x+2}{(x+3)(x-3)}$, we can find the domain $x\ne\pm3$ or $\{x|x\ne\pm3 \}$
Step 2. We can find horizontal asymptote(s) H.A. $y=0$, vertical asymptote(s) V.A. $x=\pm3$, oblique asymptote(s) O.A. $none$.
