Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Review - Review Exercises - Page 925: 4



Work Step by Step

We will use the following limit rules for this problem: $ \ Rule -\ 1 \ : \lim\limits_{x \to a} [A(x)]^n =[\lim\limits_{x \to a} A(x)]^n $ $\ Rule \ - \ 2 : \lim\limits_{x \to a} A(x)=A(a)$ Apply the given rules: $\lim\limits_{x\to 1}(\sqrt {1-x^2})=[\lim\limits_{x\to 1}\sqrt {1-x^2}]\\=\sqrt {1-1^2} \\=\sqrt {0}\\=0$
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