Answer
continuous
Work Step by Step
Evaluate the limit
$\lim_{x\to -2}\frac{x^2-4}{x+2}=
\lim_{x\to -2}\frac{(x-2)(x+2)}{x+2}=
\lim_{x\to -2}(x-2)=-4$
Thus $f(x)$ is continuous at $x=-2$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Review - Review Exercises - Page 925: 15
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