Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Review - Review Exercises - Page 925: 2

Answer

$25$

Work Step by Step

Recall the limit rules: $ \ Rule \space1 : \lim\limits_{x \to a} [A(x)]^n =[\lim\limits_{x \to a} A(x)]^n $ $\ Rule \space2 : \lim\limits_{x \to a} A(x)=A(a)$ $\ Rule \space3: \lim\limits_{x \to a} \dfrac{A(x)}{B(x)}=\dfrac{\lim\limits_{x \to a} A(x)}{\lim\limits_{x \to a} B(x)}$ Apply Rules: $(1)$ and $(2)$ $\lim\limits_{x \to a} [A(x)]^n =[\lim\limits_{x \to a} A(x)]^n $ and $ \lim\limits_{x \to a} A(x)=A(a)$ $\lim\limits_{x\to -2}(x^2+1)^2\\ =\left[(-2)^2+1\right]^2 \\=(4+1)^2 \\=5^2 \\=25$
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