Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$25$
Recall the limit rules: $\ Rule \space1 : \lim\limits_{x \to a} [A(x)]^n =[\lim\limits_{x \to a} A(x)]^n$ $\ Rule \space2 : \lim\limits_{x \to a} A(x)=A(a)$ $\ Rule \space3: \lim\limits_{x \to a} \dfrac{A(x)}{B(x)}=\dfrac{\lim\limits_{x \to a} A(x)}{\lim\limits_{x \to a} B(x)}$ Apply Rules: $(1)$ and $(2)$ $\lim\limits_{x \to a} [A(x)]^n =[\lim\limits_{x \to a} A(x)]^n$ and $\lim\limits_{x \to a} A(x)=A(a)$ $\lim\limits_{x\to -2}(x^2+1)^2\\ =\left[(-2)^2+1\right]^2 \\=(4+1)^2 \\=5^2 \\=25$