Answer
$a_1=3 \\ a_2=2 \\ a_3=\dfrac{4}{3} \\a_4=\dfrac{8}{9} \\a_5=\dfrac{16}{27}$
Work Step by Step
We are given:
$\{a_n\}=\dfrac{2}{3}a_{n-1}$ and $a_1=3$
In order to determine the remaining values, we will have to substitute $n=1, 2,3,4,5$ into the given sequence.
$a_2=\dfrac{2}{3}a_1=\dfrac{2}{3}3=2 \\ a_3=\dfrac{2}{3}a_2=\dfrac{2}{3}2=\dfrac{4}{3} \\a_4=\dfrac{2}{3}a_3=\dfrac{2}{3} \cdot \dfrac{4}{3}=\dfrac{8}{9} \\a_5=\dfrac{2}{3} a_4=\dfrac{2}{3} \cdot \dfrac{8}{9}=\dfrac{16}{27}$