Answer
$\dfrac{9}{2}$
Work Step by Step
An infinite geometric series is said to converge if and only if $|r|\lt1$, and their sum can be expressed as: $a_n=\dfrac{a_1}{1-r}$
where $a_1=\ First \ Term$ and $r$ is the common ratio of the quotient of two consecutive terms:
So, $r=\dfrac{a_2}{a_1}=\dfrac{1}{3}=\dfrac{1}{3}; |\dfrac{1}{3}|\lt1$ and $a_1=3$
Therfore, the series converges and its sum is: $a_n=\dfrac{3}{1-\dfrac{1}{3}}=\dfrac{9}{2}$
