Answer
$2, 1, 8/9, 1, 32/25$
Work Step by Step
We are given:
$\{c_n\}=\dfrac{2^n}{n^2}$
In order to determine the remaining values, we will have to substitute $n=1, 2,3,4,5$ into the given sequence. Thus:
$c_1=\dfrac{2^1}{1^2}=2 \\c_2=\dfrac{2^2}{2^2}=1 \\c_3=\dfrac{2^3}{3^2}=\dfrac{8}{9} \\c_4=\dfrac{2^4}{4^2}=1 \\c_5=\dfrac{2^5}{5^2}=\dfrac{32}{25}$
