Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 11 - Sequences; Induction; the Binomial Theorem - Chapter Review - Review Exercises - Page 859: 11

Answer

geometric, $r=\frac{1}{2}$ $S_n=6(1-(\frac{1}{2})^n)$

Work Step by Step

1. Based on the given sequence, we can determine it is geometric, 2. We can find the common ratio as $r=\frac{s_2}{s_1}=\frac{3/2}{3}=\frac{1}{2}$ 3. We can find the sum of the first n terms as $S_n=\frac{s_1(r^n-1)}{r-1}=\frac{3((1/2)^n-1)}{1/2-1}=6(1-(\frac{1}{2})^n)$
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