Answer
$10$
Work Step by Step
Recall the combination formula:
$\dbinom{n}{m}=\dfrac{n!}{(n-m)! \ m!}$.
Therefore, we have:
$$\dbinom{5}{2}=\dfrac{5!}{(5-2)!\ 2!} \\=\dfrac{5\cdot4\cdot3\cdot2\cdot1}{3\cdot2\cdot1\cdot2\cdot1}\\ =10$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 11 - Sequences; Induction; the Binomial Theorem - Chapter Review - Review Exercises - Page 859: 29
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