Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 34

Answer

$15\sqrt[3]{3}$

Work Step by Step

We simplify by using the fact that $\sqrt[n]{a}=a^{1/n}$ and then combine the like terms as follows: $$ 9\sqrt[3]{24}-\sqrt[3]{81}=9\sqrt[3]{3\times 2^3}-\sqrt[3]{3\times3^3}=18\sqrt[3]{3}-3\sqrt[3]{3}\\ =(18-3)\sqrt[3]{3}=15\sqrt[3]{3} .$$
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