Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 25

Answer

$12\sqrt3$

Work Step by Step

We apply the rule: $\sqrt{a}\sqrt{b}=\sqrt{ab}$ Thus, we have: $$ (3\sqrt{6})(2\sqrt{2})=6\sqrt{6\times2}=6\sqrt{3\times2\times2}\\ =6\sqrt{3\times2^2}=12\sqrt3 .$$
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