Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 11


$2\sqrt 2$

Work Step by Step

For positive real numbers $a$ and $b$, $\sqrt{a}\cdot \sqrt{b}=\sqrt{ab}$. Thus, $ \sqrt{8}=\sqrt{4\cdot2}=\sqrt4 \cdot \sqrt2=2\sqrt 2 $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.