Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A60: 26



Work Step by Step

We apply the rule: $\sqrt{a}\sqrt{b}=\sqrt{ab}$ Thus, we have: $$ (5\sqrt{8})(-3\sqrt{3})=-15\sqrt{8\times3}=-15\sqrt{2^2\times2\times3}\\ =-30\sqrt6 .$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.